You Are Riding Your Bike Downtown At A Speed Of 15 M/S And You See A Red Light Ahead. You Gently Break Over The Distance Of 50m And Come To A Complete
you are riding your bike downtown at a speed of 15 m/s and you see a red light ahead. You gently break over the distance of 50m and come to a complete stop what is your acceleration this time?
Good Day....
Problem:
you are riding your bike downtown at a speed of 15 m/s and you see a red light ahead. You gently break over the distance of 50m and come to a complete stop what is your acceleration this time?
Given Data:
Vi (initial velocity) = 15 m/s
Vf (final velocity) = 0 m/s (complete stop)
d (ditance) = 50 m
a (acceleration) = ? unknown
Solution:
To solve this problem, we can use the formula Vf^2 = Vi^2 + 2ad
To solve for a (acceleration), we will use a = Vf^2 - Vi^2 / 2d
a = Vf^2 - Vi^2 / 2d
= (0 m/s)^2 - (15 m/s)^2 / 2 (50 m)
= 0 - 225 m^2/s^2 / 100 m
= - 2.25 m/s^2
Answer:
acceleration is - 2.25 m/s^2 (negative since its decelerating)
Hope it helps...=)
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