You Are Riding Your Bike Downtown At A Speed Of 15 M/S And You See A Red Light Ahead. You Gently Break Over The Distance Of 50m And Come To A Complete

you are riding your bike downtown at a speed of 15 m/s and you see a red light ahead. You gently break over the distance of 50m and come to a complete stop what is your acceleration this time?

Good Day....

Problem:

you are riding your bike downtown at a speed of 15 m/s and you see a red light ahead. You gently break over the distance of 50m and come to a complete stop what is your acceleration this time?

Given Data:

Vi (initial velocity) = 15 m/s

Vf (final velocity) = 0 m/s (complete stop)

d (ditance)     = 50 m

a (acceleration) = ? unknown

Solution:

To solve this problem, we can use the formula Vf^2 = Vi^2 + 2ad

To solve for a (acceleration), we will use a = Vf^2 - Vi^2 / 2d

a = Vf^2 - Vi^2 / 2d

  = (0 m/s)^2 - (15 m/s)^2 / 2 (50 m)

  =  0 - 225 m^2/s^2 / 100 m

  = - 2.25 m/s^2

Answer:

acceleration is - 2.25 m/s^2 (negative since its decelerating)

Hope it helps...=)


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